Heat and Thermal ExpansionHard
Question
A system S receives heat continuously from an electrical heater of water 10W. The temperature of S becomes constant at 50oC when the surrounding temperature is 20oC After the heater is switch off, S cools from 35.1oC to 34.9oC in 1 minuteThe heal capacity S is: -
Options
A.100 J / oC
B.300 J / oC
C.750 J / oC
D.1500 J / oC
Solution
Rate of cooling
= ms
= 4σAT03ᐃT
⇒ 4σA × T03ᐃ (50 - 20) = 10
and 4σA × T03ᐃ (35 - 20) = ms = ms 
⇒ ms =
= 1500 J / oC
= ms
= 4σAT03ᐃT⇒ 4σA × T03ᐃ (50 - 20) = 10
and 4σA × T03ᐃ (35 - 20) = ms
= ms ⇒ ms =
= 1500 J / oCCreate a free account to view solution
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