Ionic EquilibriumHard
Question
Auto-ionisation of liquid NH3 is
2NH3 ⇋NH4+ + NH2-
with KNH3 = [NH4+] [NH2-] = 10-30 at -50oC
Number of amide ions (NH2-), present per mm3 of pure liquid NH3 is
2NH3 ⇋NH4+ + NH2-
with KNH3 = [NH4+] [NH2-] = 10-30 at -50oC
Number of amide ions (NH2-), present per mm3 of pure liquid NH3 is
Options
A.602
B.301
C.200
D.100
Solution
2NH3 ⇋ NH4+ + NH2-
[NH4+] = [NH2-] =
= 10-15 M
1 dm3 of solution contains 10-15 moles = 6.02 × 1023 × 10-15 molecules of NH2-.
1 mm3 of solution contains 6.02 × 1023 × 10-15 × 10-6 = 602 NH2- ions.
[NH4+] = [NH2-] =
1 dm3 of solution contains 10-15 moles = 6.02 × 1023 × 10-15 molecules of NH2-.
1 mm3 of solution contains 6.02 × 1023 × 10-15 × 10-6 = 602 NH2- ions.
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
Which of the following ids the strongest acid ?...The solubility product of a salt having general formula MX2, in water is: 4 × 10-12. The concentration of M2+ ions ...Let the solubility of an aqueous solution of Mg(OH)2 be x then its ksp is...What is the solubility of Al(OH)3, (Ksp = 1 × 10-33) in a buffer solution pH = 4 ?...When 0.1 mole solid NaOH is added in 1lt of 0.1 M NH3(aq) then which statement is wrong? (Kb = 2 × 10-5, log 2 = 0....