Ionic EquilibriumHard
Question
Auto-ionisation of liquid NH3 is
2NH3 ⇋NH4+ + NH2-
with KNH3 = [NH4+] [NH2-] = 10-30 at -50oC
Number of amide ions (NH2-), present per mm3 of pure liquid NH3 is
2NH3 ⇋NH4+ + NH2-
with KNH3 = [NH4+] [NH2-] = 10-30 at -50oC
Number of amide ions (NH2-), present per mm3 of pure liquid NH3 is
Options
A.602
B.301
C.200
D.100
Solution
2NH3 ⇋ NH4+ + NH2-
[NH4+] = [NH2-] =
= 10-15 M
1 dm3 of solution contains 10-15 moles = 6.02 × 1023 × 10-15 molecules of NH2-.
1 mm3 of solution contains 6.02 × 1023 × 10-15 × 10-6 = 602 NH2- ions.
[NH4+] = [NH2-] =
1 dm3 of solution contains 10-15 moles = 6.02 × 1023 × 10-15 molecules of NH2-.
1 mm3 of solution contains 6.02 × 1023 × 10-15 × 10-6 = 602 NH2- ions.
Create a free account to view solution
View Solution FreeMore Ionic Equilibrium Questions
pH of a 0.1 M monobasic acid is found to be 2. Hence its osmotic pressure at a given temperature TK is :-...Phenol on treatment with CO2 in the presence of NaOH followed by acidification produces compound X as the major product....A solution containing a mixture of 0.05 M NaCl and 0.05 M NaI is taken (Ksp of AgCl = 10-10 and Ksp of AgI = 4 × 10...Which set is not correct for the solubility product (KSP), solubility (sg/litre) of sparingly soluble salt A3B2 (mol. wt...In which of the following acid-base titration, pH is greater than 8 at equivalencepoint....