Heat and Thermal ExpansionMedium
Question
Figure shows the variation of the internal energy U with density ρ of one mole of an ideal monatomic gas for thermodynamic cycle ABCA. Here process AB is a a part of rectangular hyperbola :-
Options
A.process AB is isothermal & net work in cycle is done by gas.
B.process AB is isoberic & net work in cycle is done by gas.
C.process AB is isoberic & net work in cycle is done on the gas.
D.process AB is adiabatic & net work in cycle is done by gas.
Solution
For the process AB : = constant (hyperbola)
U =
RT (monoatomic ideal gas); ρ RT = constant
Comparing it with ideal gas equation P =
ρ RT ⇒ P = constant.
P-V graph for the cycle is
. Thus work done in cycle is positive
U =
RT (monoatomic ideal gas); ρ RT = constantComparing it with ideal gas equation P =
ρ RT ⇒ P = constant.P-V graph for the cycle is
. Thus work done in cycle is positiveCreate a free account to view solution
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