Rotational MotionMedium
Question
A wheel of radius 0.4 m can rotate freely about its axis as shown in the figure. A string is wrapped over its rim and a mass of 4 kg is hung. An angular acceleration of 8 rad-s2 is produced in it due to the torque. Then moment of inertia of the wheel is (g = 10 ms-2)
Options
A.2kg - m2
B.1 kg - m2
C.4 kg - m2
D.8 kg - m2
Solution
Given, r = 0.4 m,α = 8 rad s-2
m = 4 kg, I = ?
Torque, τ = Iα = mgr ⇒ 4 × 10 × 0.4 = I × 8
⇒ I =
= 2kg - m2
m = 4 kg, I = ?
Torque, τ = Iα = mgr ⇒ 4 × 10 × 0.4 = I × 8
⇒ I =
= 2kg - m2Create a free account to view solution
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