VectorHard
Question
The period of oscillation of a simple pendulum is given by T = 2π 
where l is about 100 cm and is known to have 1mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stop watch of least count 0.1s. The percentage error in g is :-
where l is about 100 cm and is known to have 1mm accuracy. The period is about 2s. The time of 100 oscillations is measured by a stop watch of least count 0.1s. The percentage error in g is :-Options
A.0.1%
B.1%
C.0.2%
D.0.8%
Solution
% error in length = 
× 100 = 0.1%
% error in time =
× 100 = 0.05%
% error in g = % ε in l + 2 times (% ε in T) = 0.2%
× 100 = 0.1%% error in time =
× 100 = 0.05%% error in g = % ε in l + 2 times (% ε in T) = 0.2%
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