Work, Power and EnergyHard
Question
A locomotive of mass m starts moving so that its velocity varies according to the law v = k√s where k is constant and s is the distance covered. Find the total work performed by all the forces which are acting on the locomotive during the first t seconds after the beginning of motion
Options
A.W = 
mk4t2
mk4t2B.W = 
m2k4t2
m2k4t2C.W = mk4t4
mk4t4D.W = 
mk4t4
mk4t4Solution
v = 
= k√s
∴
s-1/2 ds = k 
dt
2√s = kt
∴ s =
Wd = ᐃk =
mv2
=m(k2s)
=m(k2s)
=m(k2s)
Wd =
mk4t2
= k√s∴
s-1/2 ds = k dt2√s = kt
∴ s =
Wd = ᐃk =
mv2=
m(k2s)=
m(k2s)=
m(k2s)Wd =
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