Work, Power and EnergyHard
Question
A locomotive of mass m starts moving so that its velocity varies according to the law v = k√s where k is constant and s is the distance covered. Find the total work performed by all the forces which are acting on the locomotive during the first t seconds after the beginning of motion
Options
A.W = 
mk4t2
mk4t2B.W = 
m2k4t2
m2k4t2C.W = mk4t4
mk4t4D.W = 
mk4t4
mk4t4Solution
v = 
= k√s
∴
s-1/2 ds = k 
dt
2√s = kt
∴ s =
Wd = ᐃk =
mv2
=m(k2s)
=m(k2s)
=m(k2s)
Wd =
mk4t2
= k√s∴
s-1/2 ds = k dt2√s = kt
∴ s =
Wd = ᐃk =
mv2=
m(k2s)=
m(k2s)=
m(k2s)Wd =
mk4t2Create a free account to view solution
View Solution FreeMore Work, Power and Energy Questions
A body weighing 80N is moved up a slope of angle 60o with the horizontal through a displacement of 1m. The energy of the...A crane lifts 300 kg weight from earth′s surface upto a height of 2m in 3 seconds. The average power generated by ...A body projected vertically from the earth reaches a height equal to earth′s radius before returning to the earth....Consider the following two statements. (1) Linear momentum of a system of particles is zero. (2) Kinetic energy of syste...A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant tangential acceleration. Whatis the magnit...