Geometrical OpticsHard
Question
A point source of light B is placed at a distance L in front of the centre of a mirror of width d hung vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror at a distance 2L from it as shown. The greatest distance over which he can see the image of the light source in the mirror is
Options
A.d/2
B.d
C.2d
D.3d
Solution
According to the following ray diagram
HI = AB = d and DS = CD =
∵ AH = 2AD ⇒ GH = 2CD =
= d Similarly IJ = d so GJ = GH + HI + IJ
= d + d + d = 3d
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