Rotational MotionHard
Question
A coin placed on a rotating table just slips if it is placed at a distance 4r from the centre. On doubling the angular velocity of the table, the coin will just slip when at a distance from the centre equal to:-
Options
A.
B.
C.r
D.4r
Solution
The coin will slip from the table when the inertial force mrω2 is greater or equal to the static force of friction mg.
mrω2 ≥ μmg
r ≥
From here r ∝
∴
= 4
⇒ r2 =
= r
mrω2 ≥ μmg
r ≥
From here r ∝
∴
= 4⇒ r2 =
= rCreate a free account to view solution
View Solution FreeMore Rotational Motion Questions
Figure shows a uniform disk, with mass M = 2.4 kg and radius R = 20 cm, mounted on a fixed horizontal axle. A block of m...A 2m long rod of negligible mass is free to rotate about its centre. An object of mass 5 kg is threaded into the rod at ...A small block of mass ′m′ is rigidly attached at ′P′ to a ring of mass ′3m′and radiu...Moment of inertia, rotational kinetic energy and angular momentum of a body are I, E and L then:...Consider a thin uniform square sheet made of a right material . If its side is ′a′, mass m and moment of ine...