Rotational MotionHard
Question
A coin placed on a rotating table just slips if it is placed at a distance 4r from the centre. On doubling the angular velocity of the table, the coin will just slip when at a distance from the centre equal to:-
Options
A.
B.
C.r
D.4r
Solution
The coin will slip from the table when the inertial force mrω2 is greater or equal to the static force of friction mg.
mrω2 ≥ μmg
r ≥
From here r ∝
∴
= 4
⇒ r2 =
= r
mrω2 ≥ μmg
r ≥
From here r ∝
∴
= 4⇒ r2 =
= rCreate a free account to view solution
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