Sound WavesHard

Question

A massless rod is suspended by two identical strings AB and CD of equal length. A block of mass m is suspended from point O such that BO is equal to ′x′ Further, it is observed that the frequency of 1st harmonic (fundamental frequency) in AB is equal to 2nd harmonic frequency in CD. Then, length of BO is :
         

Options

A.
B.
C.
D.

Solution

         
According to question

T2 = T1/4
For rotational equilibrium,
T1x = T2(L - x) ⇒ x = L/5

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