Straight LineHard
Question
If the straight lines 
are coplanar, then the plane(s) containing these two lines is(are)
are coplanar, then the plane(s) containing these two lines is(are)Options
A.y + 2z = - 1
B.y + z = - 1
C.y - z = - 1
D.y - 2z = - 1
Solution
For given lines to be coplanar, we get
= 0 ⇒ k2 = 4, k = 
2
For k = 2, obviously the plane y + 1 = z is common in both lines
For k = - 2, family of plane containing first line is x + y + λ (x - z - 1) = 0
Point (- 1, - 1, 0) must satisfy it
- 2 + λ (- 2) = 0 ⇒ λ = - 1
⇒ y + z + 1 = 0.
= 0 ⇒ k2 = 4, k = 2For k = 2, obviously the plane y + 1 = z is common in both lines
For k = - 2, family of plane containing first line is x + y + λ (x - z - 1) = 0
Point (- 1, - 1, 0) must satisfy it
- 2 + λ (- 2) = 0 ⇒ λ = - 1
⇒ y + z + 1 = 0.
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