Quadratic EquationHard
Question
Let α (a) and β (a) be the roots of the equation 
where a > - 1. Then 
α(a) and β(a) are
where a > - 1. Then α(a) and β(a) are Options
A.
and 1
and 1B.
and - 1
and - 1C.
and 2
and 2D.
and 3
and 3Solution
Let 1 + a = y
⇒ (y1/3 - 1) x2 + (y1/2 - 1)x + y1/6 - 1 = 0
Now taking
on both the sides
⇒ 2x2 + 3x + 1 = 0
x = - 1, -
⇒ (y1/3 - 1) x2 + (y1/2 - 1)x + y1/6 - 1 = 0
Now taking
on both the sides ⇒ 2x2 + 3x + 1 = 0
x = - 1, -
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