Area under the curveEasy

Question

Let S be the area of the region enclosed by y = e-x2, y = 0, x = 0 and x = 1. Then

Options

A.
B.
C.
D.

Solution

              
            (As area of rectangle OCDS = 1/e)
Since e-x2 ≥ e-x ∀ x ∈ [0, 1]

Area of rectangle OAPQ + Area of rectangle QBRS > S

Since Hence, (C) is incorrect.

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