Maxima and MinimaHard

Question

f(x) = . Then f(x) has -

Options

A.jump of discontinuity at x = 0 is 2
B.a point of maxima at x = - 2 and a point of minima at x = 2
C.a point of minima at x = - 2 and a point of maxima of x = 2
D.no stationary point

Solution

         
A(2, √5)
B(-2, √5)
f(x) =
       
clearly x = - 2 is point of min
x = 2 is point of max

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