Quadratic EquationHard

Question

If a, b, c, d ∈ R such that , then equation ax3 + bx2 + cx + d = 0 will have-

Options

A.at least one root in (-1, 0)
B.at least one root in (0, 1)
C.at least two roots in (-1, 1)
D.no root in (-1, 1)

Solution

= 0 ⇒ 3a + 4b + 6c + 12d = 0
(ax3 + bx2 + cx + d) dx = (3a + 4b + 6c + 12d) = 0
⇒ f(x) has at least one root in (0,1)

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