Surface ChemistryHard
Question
A line l passing through the origin is perpendicular to the lines
Then , the coordinate(s) of the point(s) on l2 at a distance of
from the point of intersection of l and l1is(are) -
Then , the coordinate(s) of the point(s) on l2 at a distance of
from the point of intersection of l and l1is(are) -Options
A.
B.(-1,-1,0)
C.(1,1,1)
D.
Solution
(3, - 1, 4) + (1, 2, 2)t
(3, 3, 2) + (2, 2, 1)svector perpendicular to l and l2 :
∴ Equation of line l :
Point of intersection of l and l
3 + t = -2 λ.
-1 + 2t = 3 λ.
4 + 2t = -2 λ.
On solving we getλ = -1, t = -1
∴ Point of intersection of l1 and l
A point on l2 at distance of
from P :⇒ (1 + 2s)2 + (6 + 2s)2 + s2 = 17
⇒
: = - 2for above s, point will be (B), (D)
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