CapacitanceHard
Question
A conducting wire of length l and mass m can slide without friction on two parallel rails and is connected to capacitance C. Whole system lies in a magnetic field B and a constant force F is applied to the rod. Then
Options
A.The rod moves with constant velocity
B.the rod moves with constant acceleration
C.there is constant charge on the capacitor.
D.charge on the capacitor increases with time
Solution
Let velocity of wire at time t is v, then
ε = Bvl
q = Cε, i =
= CBla
Fm = ilB
F - Fm = ma
ε = Bvl
q = Cε, i =
= CBlaFm = ilB
F - Fm = ma
Create a free account to view solution
View Solution FreeMore Capacitance Questions
Three capacitors of value 6, 3 and 9 μF are joined according to the circuit and then the combination is connected w...Keeping a capacitor connected with a battery a dielectric sheet is placed between its plates. In this process....Two insulating plates are both uniformly charged in such a way that the potential difference between them is V2 - V1 = 2...In the given circuit, with steady state, the potential difference across the capacitor must be :-...The distance between the plates of a circular parallel plate capacitor of diameter 40 mm, whose capacity is equal to tha...