Momentum and CollisionHard
Question
A uniform rod AB of mass M is attached to a hinge at one end A, and released from rest from the horizontal position. The rod rotates about A, and when it reaches the vertical position the rod strikes a sphere of mass m and radius r initially at rest on the smooth horizontal surface as shown in the adjacent figure. The impact is along the horizontal direction and perfectly elastic. If at the moment of impact thelowest end of the rod is very close to the smooth horizontal surface. After the impact, the sphere moves along the horizontal and the rod, subsequently rises to a maximum of 60o with the vertical. Choose the correct statement(s) from the following, taking into account the information given above. The length of the rod equals √2r . 
Options
A.The ratio 
B.The ratio 
C.The speed of the sphere just after collision is 6 m/s
D.The speed of the sphere just after collision is 3 m/s
Solution
Mg
ω =
e =
= 1
COAM,
ω0 = ω + mv(L - r)
ω =
e =
= 1COAM,
ω0 = ω + mv(L - r)Create a free account to view solution
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